Part A What is the charge on each capacitor in the figure, if V = 7.0 V ?(Figure
ID: 2317824 • Letter: P
Question
Part A
What is the charge on each capacitor in the figure, if V = 7.0 V ?(Figure 1)
Enter your answers numerically separated by commas.
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Part B
What is the potential difference across each capacitor in the figure?
Enter your answers numerically separated by commas.
Submit
Part A
What is the charge on each capacitor in the figure, if V = 7.0 V ?(Figure 1)
Enter your answers numerically separated by commas.
Q1, Q2, Q3= CSubmitMy AnswersGive Up
Part B
What is the potential difference across each capacitor in the figure?
Enter your answers numerically separated by commas.
V1, V2, V3 = VSubmit
Explanation / Answer
a) Collapse C2 and C3 are in series
the equivalent capacitor C4
C4 = 1/(1/C2 + 1/C3) = 1/(1/4 + 1/6)
= 2.4 F
C4 and C1 are in parallel
equivalent capacitor C5 = C1 + C4 = 5 + 2.4 = 7.4 F
C5 in the only element in the circuit with the battery
the total charge on the equivalent capacitor C5 is
Q = CV = (7.4*10^-6F)(7V) = 5.18*10^-5 C
the equivalent capacitors because C4 and C1 are in parallel
Q1 = C1*V = (5 F)(7V) = 35 C
Q4 = C4* = (2.4 F)(7V) = 16.8 C
C2 and C3 they are in series the charge on each is the same.
So, Q2 = Q3 = 16.8 C.
b) the charge on each C1, C2 and C3
Q = CV => V = Q/C
V1 = Q1/C1 = 35C/5 F = 7 V
V2 = Q2/C2 = 16.8 C/4 F = 4.2 V
V3 = Q3/C3 = 16.8 C/6 F = 2.8 V