Please answer problem 3 and 4 in its entirety and show work. 3. (4 points) (the
ID: 2329042 • Letter: P
Question
Please answer problem 3 and 4 in its entirety and show work.
3. (4 points) (the principal amount) plus a monthly interest rate of 4%, paying it in equal amounts at the start of each of the following four months. How much will you be paying her and when? Today, you are borrowing $1,000 from a friend. She wants you to return that money HINT: use the formula from question 1 .assume the amount you are looking for is X draw a cash flow diagram showing each ?X .convert each X back to a present value; write down in an equation that when they are added, they should total the amount borrowed. solve for X points) amount of S100 at compound interest, compounded annually for 12 years. 4. (2 For ie 5%, find the difference between the amount of $100 at simple interest and theExplanation / Answer
Answer for Question No. 3
We will use discounting method to solve the question :
Formula is X (FV) = PV x ( 1 + r/12)nx12 Therefore total X = 1050.91$
Principal is 1000$ & Interest is 50.91$
Month
Cash Flow (PV)
No. of Months Interest Received (n)
Calculation X = CF x ( 1 + r/12)nx12
Therefore, X = by solving equation
1
250
4
X = 250x(1+0.04/12)4x12
250x(1.0033)48 = 270.57
2
250
3
X = 250x(1+0.04/12)3x12
250x(1.0033)36 = 265.27
3
250
2
X = 250x(1+0.04/12)2x12
250x(1.0033)24 = 260.08
4
250
1
X = 250x(1+0.04/12)1x12
250x(1.0033)12 = 254.99
Converting X into Present value by following equation
PV = FV / (1 + r)n therefor PV = 1050.91 ( 1 + 0.04/12 ) 4x12 = 1000$ approx.
Answer of Question No. 4
X = Future Value, P = Principle (100$), n = Time & r = rate of interest (5%)
Simple Interest
FV = P (1+nr)
X = 100 [1+(12*0.05)]
X = 160 $
Compound Interest
FV = P (1+r)n
X = 100 (1+0.05)12
X = 134 $
Therefore Difference between Simple & Compound Interest rate is 26$ (160$ - 134$)
Month
Cash Flow (PV)
No. of Months Interest Received (n)
Calculation X = CF x ( 1 + r/12)nx12
Therefore, X = by solving equation
1
250
4
X = 250x(1+0.04/12)4x12
250x(1.0033)48 = 270.57
2
250
3
X = 250x(1+0.04/12)3x12
250x(1.0033)36 = 265.27
3
250
2
X = 250x(1+0.04/12)2x12
250x(1.0033)24 = 260.08
4
250
1
X = 250x(1+0.04/12)1x12
250x(1.0033)12 = 254.99