Here is the original question for background: (2 X-linked Loci) The FI progeny f
ID: 259187 • Letter: H
Question
Here is the original question for background: (2 X-linked Loci)
The FI progeny for this original cross result in females that are both: X^hC X^Hc
MY QUESTION: “can the F1 females resulting from the above cross (which are X^hC X^Hc) have a son that is colorblind and hemophilic?”
The answer is yes but I do not understand why. I thought the answer was no.
The F1 females are X^hC X^Hc . My thoughts were that the male offspring of the F1 cross will have to take one of the female F1 X chromosomes, resulting in the offspring being are X^hC Y or X^Hc Y . Neither of these are both colorblind and hemophilic.
Can you help explain to me why the answer is yes?
Explanation / Answer
Answer:
Yes, the female can have the child with diseases, hemophilia and colorblindness. Due to independent assortment of allele, four types of gametes or eggs are produced from that F1 female, X^hC X^Hc. Those are as follows.
X^hC
X^Hc
X^hc
X^HC
If the gamete (egg) with genotype X^hc fuses with sperm of Y chromosome, the genotype of son would be X^hc Y. This genotype indicates the son with both diseases.