Please use R program do it! area acres.soy bushels.soy 1 1127 124900 2 1231 9570
ID: 2929655 • Letter: P
Question
Please use R program do it!
area acres.soy bushels.soy
1 1127 124900
2 1231 95700
3 1370 27846
4 3126 90000
5 879 82300
1 1819 97200
2 7362 456400
3 6697 311376
4 3145 166680
5 7502 523100
1 2692 133800
2 2876 91700
3 2647 108342
4 11126 728160
5 14401 831000
1 1625 171900
2 3310 209800
3 11616 469170
4 4992 384960
5 2354 174400
1 9079 567500
2 12418 723700
3 6359 281424
4 3892 322320
5 7869 503500
1 628 14000
2 11447 760300
3 2657 97578
4 6199 496200
5 4608 278500
Explanation / Answer
acres.soy
> sum(1127,1231,1370,3126,879)
[1] 7733
> sum(1819,7362,6697,3145,7502)
[1] 26525
> sum(2692,2876,2647,11126,14401)
[1] 33742
> sum(1625,11616,3310,492,2354)
[1] 19397
> sum(9079,12418,6359,3892,7869)
[1] 39617
> sum(628,11447,2657,6199,4608)
[1] 25539
bushels.soy
> sum(124900,95700,27846,82300,90000)
[1] 420746
> sum(97200,456400,311376,166680,523100)
[1] 1554756
> sum(133800,91700,108342,728160,831000)
[1] 1893002
> sum(171900,209800,469170,384960,174400)
[1] 1410230
> sum(567500,723700,281424,322320,503500)
[1] 2398444
> sum(14000,760300,97578,496200,278500)
[1] 1646578
Now number of bushels of soy produced / No. of acres
we get
No. of acres =
> sum(7733,26525,33742,19397,39617,25539)
[1] 152553
No. of soy brushels =
> sum(420746,1554756,1893002,1410230,2398444,1646578,152553)
[1] 9476309
ratio =
>(9476309/152553)
[1] 62.11814