See \" TABLE 1 \" above regarding data from the results of a disaster preparedne

Question

See "TABLE 1" above regarding data from the results of a disaster preparedness survey in 4 cities in California from a sample of 20 participants.

If the researcher was to choose 2 people at random (assume when a person is chosen, they are not eligible to be chosen again), what is the probability that the 1st person she chooses lives in Los Angeles and the 2nd person she chooses lives in Los Angeles?

6/20 or 30% ID# | Age | City of Residence | Earthquake kit prepared? | Experienced major earthquake? Los Angeles Los Angeles Los Angeles Los Angeles Los Angeles Los Angeles San Francisco San Francisco San Francisco San Francisco San Francisco San Francisco San Francisco San Diego San Diego San Diego Santa Cruz Santa Cruz Santa Cruz Santa Cruz 26 57 Y es 24 57 36 82 Y es 67 24 75 20

Explanation / Answer

Number of persons lives in Los Angeles = 6

Hence,

P(Both persons in Los Angeles) = (6/20)*(5/19) = 30/380 or 7.9%

Option C is correct.

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