Hi All, My problem: You have a pile of cards. Shuffled. The cards getssplit into
ID: 2950650 • Letter: H
Question
Hi All,My problem: You have a pile of cards. Shuffled. The cards getssplit into 4 piles of 13 cards each. What is the probability of the1st pile only having one ace?
This is part of a problem in "An introduction to ProbabilityModels" by Sheldon M. Ross, Chapter 1 Q26. According to Cramster'ssolution, this is 1! Obviously wrong?!
An alternate answer is that there is C(52, 4) ways of selecting the4 aces, and they can be placed in 13 to the power 4 ways, andtherefor, the probability that the 1st pile contains only 1 ace is0.11. I just don't know how to justify this 13 to the power 4 waysof placing the aces!
Could someone explain to me on how to calculate this probability indetailed steps, please?
Regards
Wayne
Explanation / Answer
the probability of the 1st pile of having one ace is(4/52).......but each pile has an equal probability of having anace and since there are 4 piles :(4/52)*4=.3077(100)=30.77% prob.