Question
Instructions to question: Identify the indicated values or interprete the given display. Usethe normal distribution as an approximation to the binomialdistribution. Question: Driving and texting: In a survey, 1864 out of 2246randomly selected adults in the UnitedStates said that textingwhile driving should be illegal. Consider a hypothesis test thatuses a 0.05 significance level to test the claim that more than 80%of adults believe that texting while driving should beillegal. a) What is the test statistic? b) What is the critical value? c) What is the P-value? d) What is the conclusion? Please i need help on this question. Step-step working Instructions to question: Identify the indicated values or interprete the given display. Usethe normal distribution as an approximation to the binomialdistribution. Question: Driving and texting: In a survey, 1864 out of 2246randomly selected adults in the UnitedStates said that textingwhile driving should be illegal. Consider a hypothesis test thatuses a 0.05 significance level to test the claim that more than 80%of adults believe that texting while driving should beillegal. a) What is the test statistic? b) What is the critical value? c) What is the P-value? d) What is the conclusion? Please i need help on this question. Step-step working
Explanation / Answer
for the given data H0: not more than 80% of adults believe thattexting while driving should be illegal. P =0.8 H1: more than 80% of adults believe that textingwhile driving should be illegal. P>0.8 the test statistic to test the above hypothesis , Z = (p - P )/(PQ/n) here , p= 1864 / 2246 =0.8299 P= 0.8 Q = 0.2 n = 2246 then , Z = ( 0.8299 - 0.8) / (0.8*0.2/2246) =0.0299 / 0.00844 = 3.5426 the P - value, P = 1-(z) = 1-(3.5426) =1- 0.999807 =0.000193 since the P-vlaue is less than the level of significance. wereject the null hypothesis hence, we conclude that more than 80% of adults believe thattexting while driving should be illegal