Please explain step by step and thank you in advance~~ Among 60 automobile repair parts loaded on a truck in SanFrancisco, 45 are destined for seattle and 15 for vancouver. if twoof the parts are unloaded in potland by mistake and the selectionis random, what are the probabilities that 1) both parts should have gone to seattle 2) both parts should have gone to vancouver 3) one should have gone to seattle and one tovancouver.. Please explain step by step and thank you in advance~~ Among 60 automobile repair parts loaded on a truck in SanFrancisco, 45 are destined for seattle and 15 for vancouver. if twoof the parts are unloaded in potland by mistake and the selectionis random, what are the probabilities that 1) both parts should have gone to seattle 2) both parts should have gone to vancouver 3) one should have gone to seattle and one tovancouver..
Explanation / Answer
a) There are 45C2 = 990 ways of picking2 seattle parts and 60C2 =1770 totalways to pick 2 parts. 990/1770=.559 b) There are 15C2 =105 ways of picking 2vanouver parts abd 60C2 =1770 total ways topick 2 parts. So 105/1770=.059 c) There are45C1*15C1=675 ways ofpicking 1 seattle and 1 for vancouver, and60C2 =1770 total ways to pick 2 parts. so675/1770=.381