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Please I need detailed answers Second question Consider power generation by an a

ID: 2998422 • Letter: P

Question

Please I need detailed answers

Second question

Consider power generation by an adiabatic steam turbine. The steam enters the turbine with a pressure of 3 MPa and temperature of 400 degree C, and leaves at 50 kPa and 150 degree C. For steady-state operation, the turbine power output is 5 MW. Neglect changes in kinetic and potential energy. Find the mass flow rate of the steam. Refrigerant 134a is to be cooled by water in a condenser The refrigerant enters the condenser with a mass flow rate of 6 kg/min at 1 MPa and 70 degree C, and leaves as a compressed liquid at 34 degree C. The cooling water enters at 300 Kpa and 15 degree C and leaves 25 degree C. Neglect any pressure drops, determine (a) The mass flow rate of the cooling water required (b) The heat transfer rate from the refrigerant to water

Explanation / Answer

(1) Given that

mass flow rate of refrigerant mr = 6 kg/min

temp at inlet of condensor of refrigerant = 70 oC

Pressure at the inlet of condensor = 1MPa

h1= 303.85 KJ/Kg

At 34 0C , h2 = 99.40 KJ/Kg

we know that heat lost by refrigerant = heat gained by water

(a) mr * (h1 - h2) = mw * Cpw * (Tw1 - Tw2)

mw = (6 * (303.85 - 99.40))/(4.187 * 10)

   = 29.29 Kg/min

(b) Heat transfer from refrigerant = mr(h1 - h2)

   = 6 (303.85 - 99.40)

   = 1226.7 KJ/min

(2) Given that P3= 3MPa; T3 = 4000C, h3 = 3231.7 KJ/Kg

   P4 = 50 KPa and h4 = 2645.2 KJ/Kg

From the steady flow energy equation,since K.E & P.E = 0

m *h3 + Q = m *h4 + W

m(h3 - h4 ) = W (since Q = 0)

Therefore m = W/(h3 - h4)

= 5000/(3231.7 - 2645.2)

= 8.52 Kg/s