A meteorologist is monitoring the atmospheric pressure at various cities whose h
ID: 3019014 • Letter: A
Question
A meteorologist is monitoring the atmospheric pressure at various cities whose height above sea level varies. The meteorologist determines that the atmospheric pressure decreases by 12% for each additional kilometer the city is above sea level. It has been determined that the atmospheric pressure at sea level is 103 kPa (kilopascals). a. Determine the atmospheric pressure in the following cities. i. A city located 9.5 km above sea level (1773 -kPa Preview 22640328.40174 ii. A city located 1.1 km above sea level 120853810147 "kPa Preview ii. A city located 11.9 km above sea level 198912713760.04a kPa Preview Define a function, k, that expresses the atmospheric pressure of the city, p, (in kPa) as a function of the number of kilometers, z, the city is above sea level. k·(17732264032·40174r. Preview above sea level (in kilometers) will the atmospheric level be less than 16 kPa? c. Use your graphing calculator to determine at what elevation w kilometers PreviewExplanation / Answer
If the pressure decreases 12% per kilometer of elevation,
then this would be the equation:
Pressure = (pressure at sea level) · (0.88)^power of (elevation in km) .
a) i) If the sea level pressure is 103 kPa and the city is 9.5 km above sea level, then
Pressure = (103 kPa)*(0.88)^9.5
= (103 kPa)*( 0.29688) = 30.6 kPa
ii) If the sea level pressure is 103 kPa and the city is 1.1 km above sea level, then
Pressure = (103 kPa)*(0.88)^1.1
= (103 kPa)*( 0.86882) = 89.5 kPa
iii) If the sea level pressure is 103 kPa and the city is 11.9 km above sea level, then
Pressure = (103 kPa)*(0.88)^11.9
= (103 kPa)*( 0.21845) = 22.5 kPa
b) Pressure = (pressure at sea level) · (0.88)^power of (elevation in km) .