Please answer all the questions 1.Multiple-choice questions each have four possi
ID: 3042931 • Letter: P
Question
Please answer all the questions
1.Multiple-choice questions each have
four possible answers left parenthesis a comma b comma c comma d right parenthesis(a, b, c, d),
one of which is correct. Assume that you guess the answers to three such questions.
Use the multiplication rule to find P(CWW), where C denotes a correct answer and W denotes a wrong answer
P(CWW)equals=
2.Assume that random guesses are made for 3 multiple-choice questions on a test with 5 choices for eachquestion, so that there are N equals=3 trials, each with probability of success (correct) given by
P equals=0.20.
(Trials: 3 0) .970 .857 .729 .512 .343 .216 .125 .064 .027 .008 .001 0+ 0+ 0 3
* 1 .029 .135 .243 .384 .441 .432 .375 .288 .189 .096 .027 .007 0+ 1 *
* 2 0+ .007 .027 .096 .189 .288 .375 .432 .441 .384 .243 .135 .029 2 *
* 3 0+ 0+ .001 .008 .027 .064 .125 .216 .343 .512 .729 .857 .970 3 *
Find the probability of no correct
answers.
(Round to three decimal places asneeded.)
3.Assume that when adults with smartphones are randomly selected, 52%
use them in meetings or classes. If 20 adult smartphone users are randomly selected, find the probability that exactly 14 of them use their smartphones in meetings or classes.
The probability is
nothing .
(Round to four decimal places as needed.)
4. Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby. This method is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect, so the probability of a girl is
0.5. Assume that the groups consist of 16
couples. Complete parts (a) through (c) below.
a. Find the mean and the standard deviation for the numbers of girls in groups of
16
births.
The value of the mean is
muequals=8 8.
(Type an integer or a decimal. Do not round.)
The value of the standard deviation is
sigmaequals=2 2.
(Round to one decimal place as needed.)
b. Use the range rule of thumb to find the values separating results that are significantly low or significantly high.
Values of
nothing
girls or fewer are significantly low.
(Round to one decimal place as needed.)
c. Is the result of girls a result that is significantly high?
What does it suggest about the effectiveness of the method? The result significantly high, because girls is nothing girls. A result of girls would suggest that the method (Round to one decimal place as needed.)
Explanation / Answer
P( CWW) = Probability of 1 correct and 2 wrong = 3C1 * (1/4)*(3/4)^2 = 27/64
2nd) P( no correct) = 0.8^5=0.32768
P( 14 use smartphone) = 20C14 *(0.52)^14 * (0.48)^6 = 20!/(14!*6!)*(0.52)^14 * (0.48)^6=0.0501
Please repost other questions individually