Course Content x D Exam, 1 (Chapters 1, 2, 3 x e Chegg Study I Guided Sc × e The
ID: 3045764 • Letter: C
Question
Course Content x D Exam, 1 (Chapters 1, 2, 3 x e Chegg Study I Guided Sc × e The Standard Deviation. x O How to take a screensho x kevin , C ezto.mheducation.com/hm.tpx Apps D Suggested Sites AOL Mail AOL G Google D New Tab D Parma Senior High- D Cleveland State Un Confirmation: Your AOL Mail (27) Time remaining: 105:38 26.00 points The following frequency distribution shows the number of passengers who flew on a small regional aircraft company's fight number 1853 for the past 50 days ulative Relative Number of passengens on Flight 1853 Fr Relative Fre to 59 06 60 to 69 to 28 40 48 50 36 24 80 to 89 12 90 to 99 100 to 109 04 Use this data to construct a relative frequency and cumulative relative frequency distribution. Report all of your answers in the table above to 2 decimal places, using conventional rounding rules. What percent of the days are there more than 89 passengers on Flight 1853? Report your final answer to 2 decimal places, using conventional rounding rules. 20 What proportion of the days are there 60-69 passengers on Flight 1853? Report your final answer to 2 decimal places, using conventional rounding rules. What percent of the days are then no more than 79 passengers on Flight 1853? Report your final answer to 2 decimal places, using conventional rounding rules. 56 What is the approximate mean number of passengers on Flight 1853? Report your final answer to 2 decimal places, using conventional rounding rules 78.7 What is the approximate standard deviation of the number passengers on Flight 1853? Report your final answer to 2 decimal places, using conventional rounding rules. 12.14 What is the midpoint of the class interval with the largest frequency? Report your final answer to 2 decimal places, using conventional rounding rules. 109.5 1031 AM 2/17/2018Explanation / Answer
a) P(X > 89) = 0.16 + 0.04 = 0.2 = 20%
b) P(60 < X < 69) = 0.14
c) P(X < 79) = 0.06 + 0.14 + 0.36 = 56%
d) Mean = 78.7
e) standard deviation = 12.14
f) Midpoint of class of highest frequency = (70 + 79) / 2 =74.5
d)