Course Content x D Exam, 1 (Chapters 1, 2, 3 x e chegg Study l Guided Sc × G Cou
ID: 3045767 • Letter: C
Question
Course Content x D Exam, 1 (Chapters 1, 2, 3 x e chegg Study l Guided Sc × G Course Content X D Exan XOPearson's Coefficient of S x kevin , C ezto.mheducation.com/hm.tpx Apps D Suggested Sites AOL Mail AOL G Google D New Tab D Parma Senior High- D Cleveland State Un Confirmation: Your AOL Mail (27) BUS 201 (Master Course-Online): Spring 2018 Tyler Deutsch BUSINESS STATISTICS (Section 50) Exam 1 (Chapters 1, 2, 3, 4) Spring 2018 instructions I help Question 9 (of 13) Save &ExSubmit; Time remalning: 0:41:42 value: 12.00 points In a quality control test of parts manufactured at Halvorson's Fittings, an engineer sampled parts produced on the first, second, and third shifts. The research study was designed to examine the quality of parts produced across the three work shifts. The data are summarized in the table below QUALITY Good Defective PRODUCTION SHIFT Second 368 Third 176 First What percent of the total parts produced were defective? ANSWER:|- What percent of the total parts were produced on the second shift? 1.89 % (report your answer to 2 decimal places, using conventional rounding rules) ANSWER 44 45 % (report your answer to 2 deci al places, using conventional rounding rules) Of the good parts that were produced, what percent were produced by the third shift? ANSWER: 21.23% (report your answer to 2 decimal places, using conventional rounding rules) of the parts that were by the first shift, what percent were good? ANSWER: 95% (report your answer to 2 decimal places, using conventional rounding rules) 10:55 AM 2/17/2018Explanation / Answer
Total production = 285 + 368 + 176 + 15 + 32 + 24 =
a) percentage of defective = (15 + 32 + 24)/900 * 100 = 7.89%
b) percentage of the total parts produced in the second shift = (368 + 32)/900 * 100 = 44.44%
c) Of the good parts , percentage were produced by third shift = 176/(285 + 368 + 176) * 100 = 21.23%
d) percentage of good, that were produced by first shift = 285/(285 + 15) * 100 = 95%