III. Use the following data to 4.3, 0.5, 0.6, 0.8,0.5, 0.4, 3.8, 1.3, 0.4, 0.3 1
ID: 3046891 • Letter: I
Question
III. Use the following data to 4.3, 0.5, 0.6, 0.8,0.5, 0.4, 3.8, 1.3, 0.4, 0.3 1. Find the percentile rank for 0.8 and 1.3 in the data set. 2. What value corresponds to 70th percentile? 3. check for outliers IV. The average college student produces 640 pounds of solid waste each year . If the standard deviation is approximately 85 pounds, within what weight limits will at least 88.89% of all students' garbage lie? Use Chebychev's Theorem. V. The reported high temperatures of the 23 cities of the United States in October are shown. Find the z value for a temperature of 80° 62, 72, 66, 79, 83, 61, 62, 85,72, 64, 74, 71, 42, 38, 91, 66, 77, 90, 74, 63, 64, 68, 42Explanation / Answer
1) Arrange the scores in ascending order.
percentile rank for 0.8
number of points = 10
below score count from 0.8= 7
same number of count =0
Therefore percentile rank is 70.
percentile rank for 1.3
Number of scores, N = 10
Below score count from 1.3 =8
Same score count = 0
Percentile Rank = 80
Values corresponding to 70th percentile is
Your input: find the 70th percentile of 43/10,1/2,3/5,4/5,1/2,2/5,19/5,13/10,25,43/10,
The pp-th percentile is a value such that at least pp percent of the observations is less than or equal to this value and at least (100p)(100p) percent of the observations is greater than or equal to this value.
The first step is to sort values.
The sorted values are 3/10,2/5,2/5,1/2,1/2,3/5,4/5,13/10,19/5,43/10
Since there are 10 values, then n=10
Now, calculate index i=p100n=7010010=7i=p100n=7010010=7.
Since index ii is an integer, the 70th percentile is the average of the values in positions i and i+1
Value at position i=7 is 45 and at position i+1=8 is 13/10
Their average is the percentile: (4/5+13/10)/2=21/20.
Answer: the 70th percentile is 21/20=1.052120=1.05.
OUtliers: 3.8, 4.3
V) mean= 68.1, n= 23 and standard deviation, S= 13.95
For X= 80
Z= Z = (X - ) /
Z = (80 - 68.1) / 13.95
Z = 0.85305
Please repost question iv. Thank you.
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