Descriptive Statistics Access tech instructions, videos,·d data sets at www. Tri
ID: 3050693 • Letter: D
Question
Descriptive Statistics Access tech instructions, videos,·d data sets at www. Trieustats.com 3-1 Basic Skills and Concepts Statistical Literacy and Critical Thinking 1. Average A report includes a statement that the "average" Medical College Admission Test (MCAT) score of applicants to medical schools is 28.4. What is the role of the term average in statistics? Should another term be used in place of average? 2. What's Wrong? The Centers for Disease Control and Prevention (CDC) publishes a list of smoking rates in each state. If we add the 50 percentages and then divide by 50, we get 1967%. Is the value of 19,67% the mean smoking rate for all of the United States? why or why not? 3. Measures of Center In what sense are the mean, median, mode, and midrange measures "center"? 4. Resistant Measures Here are five pulse rates (BPM) of females: 80, 94, 58, 66, 56. Find e mean and median of these five values. Then find the mean and median after including a sixth value of 740, which is an outlier. (One of the female pulse rates is 74, but 740 is used here as an error resulting from an incorrect data entry.) Compare the two sets of results. How much was the mean affected by the inclusion of the outlier? How much is the median affected by the inclusion of the outlier? Textbook questions Question #4, page 85 (10 points) a. The mean (n=5) b. The median (n=5). C. The mean (n=6). d. The median (n-6)_ Compare the two sets of results: How much was mean affected? How much was median affected? players from the preceding exercise). Are the results likely to be representative of all National Football League (NFL) players? 189 254 235 225 190 305 195 202 190 252 305 9. Peas in a Pod Biologists conducted experiments to determine whether a deficiency of carbon dioxide in the soil affects the phenotypes of peas. Listed below are the pheno- type codes, where = smooth-yellow, 2=smooth-green, 3=wrinkled-yellow, and continued
Explanation / Answer
Solution:
Given data:
80 , 94 , 58 , 66 , 56
Mean : average of above data = 70.8 Using excel, =AVERAGE(A1:A5)
Median: Middle value of the data after sorting = 66
Now we add 740 as an additional observation(Outlier)
Data becomes:
80 , 94 , 58 , 66 , 56 , 740
Mean : average of above data = 182.33 Using excel, =AVERAGE(A1:A6)
Median: Average of Middle 2 values of the data after sorting = 73
Now we can see original mean = 70.8 and after adding otlier mean becomes = 182.33
It clearly observe that second mean is very high due to outlier which affects more.
Now original median = 66 and second median is 73 . It does not affect as compare to mean.
Done