Ca Secure https//www net/web/Student/Assig e No, these results are not consisten
ID: 3053459 • Letter: C
Question
Ca Secure https//www net/web/Student/Assig e No, these results are not consistent since the probability is greater than 0.95 for values of n greater than 38. You may need to use the appropriate appendix table or technology to answer this quest ion. Need Help? -eBook ovt s The Environmental Protection Agency is is the concentration of the pollutant that will kill half of the test species in a given amount of time ( many studies, the val concerned with the problem of setting criteria for the amounts of certain taxic chemicals to be allowed in freshwater lakes and rivers. A of certain toxic usually 96 hours for fish species). This measure is called LC50 (lethal concentration killing s0s% of the test species). in es contained in the natural logarithm of LCs0 measurements are normally distributed, and, hance, the analysis is based on In(LC50) data. measurem (say, species A) show the varlance of In(LC50) measurements to be around 0.5 with concentration measurements in mligrams per liter. If n e s variance of In(LCs0) measurements to studies on LC50 Studies of the effects of copper on a certain species of fish copper are to be completed, find the probability that the sample mean of In(LCS0) will differ from the true population mean by no more than 0.3. (Round your answer to four decimal places.) You may need to use the appropriate appendix table or technology to answer this questio Need Help? Talk to a Titer Additional Materials eBook My - points Wackeny stac 7E 016 08 Submissions Used The Environmental Protection Agency s concerned with the problem or setting criteria or the amo nts a ceran·me en aso ?, slosen n ran anar ak-annon on est e doneti Omer an is the concentration of the pollutant that will kill half of the test species in + given amount of time (usually 96 hours for fish species). This measure is called LCS0 (lethal concentration killing 50B% of the test species), in many studies, the values contained in the natural logarithm of LC50 measurements are normally distributed. and, hence, the analysis is based on In(LC50) data. 515 PMExplanation / Answer
Here 0.3 is the spread that is allowed from the mean of the population.
SE = sqrt(0.5/8) = 0.25
As sample size is less than 30, we use t with df = 7
t = +/- 0.3/0.25 = +/- 1.2
Required Probability
P(-1.2 < t < 1.2)
= P(t < 1.2) - P(t < -1.2)
= 0.7308 .. using t table