Chapters 14, 15, 33, and 34 Problem Quiz Exercise 33.11-Enhanced-with Solution ?

Question

Chapters 14, 15, 33, and 34 Problem Quiz Exercise 33.11-Enhanced-with Solution ?) 2of20 Constants Part A As shown in the figure (Figure 1), a layer of water covers a slab of material X in a beaker. A ray of light traveling upwards follows the path indicated Using the information on the figure, find the index of refraction of material X , You may want to review (Pages 100-1086) For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Refection and tefraction Submit Part B Find the angle the light makes with the normal in the air Figure 1 of 1 Submit Air Water Next > Provide Feedback 65

Explanation / Answer

Given:

n1 = ?

n2 = n(water) = 1.33

th1 = (90-65) = 25 degrees

th2 = 48 degrees

(A) Using Snell's law of refraction:

n1 sin(th1) = n2 sin(th2)

=> n1* sin25 = 1.33*sin48

=> n1 = 2.34

(B) For water-air interface:

1.33sin48 = 1*sin(th)

=> th = 81.26 degrees

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