Chapter3 Exercises CUNJ-ING Problems 1 through 5 offer practice with the multipl
ID: 3277922 • Letter: C
Question
Chapter3 Exercises CUNJ-ING Problems 1 through 5 offer practice with the multiplication rule. A man has five pairs of pants, six shirts and two pairs of shoes. How many different outfits can be formed (with apologies for any fashion faux-pas)? 2. Pennsylvania license plates use a sequence of three letters followed by four digits. How many different license plates can be formed (with apologies for any nasty words)? 3. A menu has 4 appetizers, 5 main dishes, 3, deserts, and 7 beverages. How many different meals can be formed by selecting one choice from each category? A conference offers 3 seminars at 9:00 am, 5 seminars at 10:00 am and 4 seminars at 11:00 am. You also have the option of not How many different ways can you spend attending a seminar at any given hour your morning at the conference? and 3 seniors. A A list of students contains 6 freshman, 5 sophomores, 7 juniors, committee of four students is to be formed with one student from each class. How many different committees can be formed? Problem 6 through 10 offer practice with permutations. How many ways can five distinct books-be arranged on a shelf? How many ways can six people be arranged in a line? How many ways can the selection of a chairperson, vice-chairperson, 7. 8. secretary, and a treasurer be made from a committee of 11 people? How many ways can 12 horses finish in the order Win, Place, and Show? How many six character strings can be formed from the 26-letter alphabet if no letter 9 10. is to be repeated?Explanation / Answer
1) Number of different outfits that can be formed is computed as:
= Total number of pair of pants * Number of shirts * Number of pair of shoes
= 5*6*2
= 60
Therefore 60 outfits could be formed here.
2) The 7 characters here are:
_ _ _ _ _ _ _
The first 3 characters could be filled in 26 ways ( as there are 26 letters ) and the last 4 characters could be filled in 10 ways each ( as there are 10 digits from 0 to 9)
Therefore the total number of license plates that could be formed here would be computed as:
= 263 * 104
= 175760000
3) Number of different meals that could be formed is:
= Number of appetizers * Number of main dishes * Number of deserts * Number of beverages
= 4*5*3*7
= 420
Therefore there are 420 means possible here
4) There are a total of 4 ways to attend a seminar at 9am, 6 ways to attend a seminar at 10 am and 5 ways to attned a seminar at 11 am. Therefore number of different ways of spending the morning could be computed as:
= 4*6*5
= 120
therefore there are 120 ways to do that.