Question
For the line 4x+6y=12, find: (a) A line parallel to it containing the point (1,-1) (b) A line perpendicular to it containing the point(0,3) Show each step, how u set it up and explain how you solvedalong the way to recieve full kharma points, Thanks for thehelp For the line 4x+6y=12, find: (a) A line parallel to it containing the point (1,-1) (b) A line perpendicular to it containing the point(0,3) Show each step, how u set it up and explain how you solvedalong the way to recieve full kharma points, Thanks for thehelp
Explanation / Answer
put the line in the form y = mx + b 4x + 6y = 12 6y = -4x +12 y =(-2/3) + 2 when the line is parallel, the slope is the same, so fora parallel line use slope of -2/3 and point 1,-1 when line is perpindicular, the slope is negative recipricol,so for perpindicular line use slope of 3/2 and point 0,3 part a y + 1 = (-2/3)(x - 1) y = (-2/3)x + (2/3) -1 y = (2/3)x - (1/3) part b y - 3 = (3/2)(x - 0) y = (3/2)x + 3 the equaation i used was the slope equation, which is m = (y -y1) / (x - x1) and sub in the point forx1 and y1