Part 1 of 3 A missile isshot from a submarine 1440 feet below sea level at an in

Question

Part 1 of 3 A missile isshot from a submarine 1440 feet below sea level at an initial velocity of 528 ft/sec. A function that approximates the height of the missile (relative to sea level) by: h t) 16t 2+ 528t 1440 where h(t) is the height of the missile in feet and t is the time in seconds. Complete the table to determine the height of the missile for the given values of time, t. This is a Fill in the blanks question so please give ONLY the with no label and commas in your answers height. time, (t) Height, h(t) 15

Explanation / Answer

at t= 0

-16*0 + 528 * 0 -1440= -1440 ( negative means below the sea level , at distance 1440)

at t = 5

-16*5*5 + 528 * 5 -1440 = 800

at t = 15

-16*15*15 + 528 *15 -1440 = 2880

at t=25

-16*25*25 + 528 *25 -1440 = 1760 ( distance decreased missile returning back)

at t = 35

-16*35*35 + 528 *35 -1440 = -2560 ( returned to the sea, cameback in the water)

c) WE WANT to find two t's when missile was at sea level , h(t) = 0

solve -16t^2 + 528t -1440 = 0

t^2 - 33t + 90 = 0

t^2 -30t -3t + 90 = 0

(t-3) (t-30 ) = 0

t = 3

or t = 30

at t= 3 sec missile emerged out ofthe water

and at t= 30 sec it came back

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