I would like to get an answers # 16 and 18 use excel to resolve #18 as well plz
ID: 3127301 • Letter: I
Question
I would like to get an answers # 16 and 18 use excel to resolve #18 as well plz email it to me Wdwdmo@gmail.com Thanks in advance 339 ONE-SAMPLE TESTS OF HYPOTHESIS & ven the blowing hypotheses: H a100 A random sample of six resuted in the following values: 118, 105, 112, 119, 105, and 111 Assume a normal population. Using the.05 significance level, can we conclude the mean s difilerent from 100? a. State the decision rule b. Compute the valus of the test statistic. e. What is your decision regarding the nut hypothesis? d. Estimate thop-val 17. The amourt of water consumed each day by a heathy adult tollows a normal distibution with ameen of 1.4 liters. Ahealthcampaign promotes te consumpordeleast 20 day A sarrple of 10 adults after the campsign shows the following consumption in liters For DATA FILE. pease viit 15 16 15 14 1 14 13 118 17 At the 01 significance level can we conclude that water consumption has increased? Cal culate and interpret the p-value. shalif mean shelf life of a 5-gallorn 18. The iquid chiorine added to swimming pools to combat algae has a relatively short lfe before it loses its effectiveness. Records indicate that the ug of chlorine is 2,160 hours (90 days). As an experiment, Hoidlonger was added to the chiorine to fnd whether it would increase the shel ite A sample of nine jugs of chiorine had these sheif Ives fin hours) For DATA FILE ploace ve 215 2770 2180 2,079 2160 2167 21 2,181 2.185 At the 025 level, has Holdlonger increased the sholf ife of the chlorine? Estimate the p-value A Washington, D.C. "Think tank" announces the typical teenager sent 50 text messages per day in 2013. To update that estimate, you phone a sample of 12 teenagers and ask them how many text messages they sent the previous day Thair responses were 18. For DATA FILE. ploase vist mhhe .comind1e 51175 47 4454 145 203 21 sa 42 100; 507 Estimate he 20. Hugger Poils contends that an agent conducts a mean of 53 in-depth home surveys every At the 05 level, can you conclude that the mean number is greater than -value and describe what it tells you week, A streamlined survey fomn has been introduced, and Hugger wants to avaluate ts ffectiveness. The number of in-depth surveys conducted during a week by a random sam- ple of 15 agents are For DATA FILE, please von 16e 536750555854“5259626060515956 At the.05 level of significance, can we conclude that the mean number of interviews con ducted by the agents is more than 53 per week? Estimate the p-value. LO10 Compute the probability of a Type ll error TYPE II ERROR Recall that the level of significance, identified by the symbol a, is Recal that the level of significance, identified by the symbol a, is t the null hypothesis is rejacted when it is true. This is called a Type eorh common levels of significance are 05 and.01 and are set by the researc outset of the test In a hypothesis-testing situation there is also the possibility that a null hypothes not rejected when it is actually false. That is, we accept a false null hypothesis T called a Type ll eror. The probability of a Type ll error is identified by the Greek letter be . The following example lustrates the details of determing the value ofExplanation / Answer
16.
a) the decision rule is Reject the null hypothesis if test statistic value is > 2.57
or if the p-value is < 0.05
b) The test statistic value. t = 4.72
c) since 4.72 > 2.57, reject the null hypothesis
d) The p - value = 0.0052
18.
The test statistic value t= 3.9791
and p-value of the test statistic = 0.002033
since the test statistic value 3.979 > 2.306, conclude that Holdlonger incresed the shelf life of the chlorine