A sample of 44 observations is selected from a normal population. The sample mea
ID: 3133129 • Letter: A
Question
A sample of 44 observations is selected from a normal population. The sample mean is 24, and the population standard deviation is 3. Conduct the following test of hypothesis using the 0.05 significance level. H0: 23 H1: > 23 17. value: 10.00 points Required information a. Is this a one- or two-tailed test? One-tailed test Two-tailed test References eBook & Resources Multiple ChoiceDifficulty: 2 IntermediateLearning Objective: 10-05 Conduct a test of a hypothesis about a population mean. Check my work 18. value: 10.00 points Required information c. What is the value of the test statistic? (Round your answer to 2 decimal places.) Value of the test statistic References eBook & Resources WorksheetDifficulty: 2 IntermediateLearning Objective: 10-05 Conduct a test of a hypothesis about a population mean. Check my work 19. value: 10.00 points Required information d. What is your decision regarding H0? Reject H0 Fail to reject H0 References eBook & Resources Multiple ChoiceDifficulty: 2 IntermediateLearning Objective: 10-05 Conduct a test of a hypothesis about a population mean. Check my work 20. value: 10.00 points Required information e. What is the p-value? (Round your answer to 4 decimal places.) p-value
Explanation / Answer
17.
Formulating the null and alternative hypotheses,
Ho: u <= 23
Ha: u > 23
As we can see, this is a right tailed test.
Hence, it is a ONE TAILED TEST. [ANSWER]
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18.
Getting the test statistic, as
X = sample mean = 24
uo = hypothesized mean = 23
n = sample size = 44
s = standard deviation = 3
Thus, z = (X - uo) * sqrt(n) / s = 2.211083194 [ANSWER, TEST STATISTIC]
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19.
Thus, getting the critical z, as alpha = 0.05 ,
alpha = 0.05
zcrit = + 1.644853627
Also, the p value is
p = 0.013515038
As z > 1.645, and P < 0.05, we REJECT THE NULL HYPOTHESIS.
ANSWER: REJECT HO
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20.
As this is one tailed, the p value is
p = 0.013515038 [ANSWER]