A sample of 4.00 g of methane is mixed with 15.0 g of chlorine with the followin

Question

A sample of 4.00 g of methane is mixed with 15.0 g of chlorine with the following equation: CH4 (g) + 4 Cl2 (g) = CCl4 (l) + 4HCl (g) Determine which reactant is the limiting and the calculate the maximum mass of CCl4 that can be formed. Calculate the theoretical yield. A sample of 4.00 g of methane is mixed with 15.0 g of chlorine with the following equation: CH4 (g) + 4 Cl2 (g) = CCl4 (l) + 4HCl (g) Determine which reactant is the limiting and the calculate the maximum mass of CCl4 that can be formed. Calculate the theoretical yield. Determine which reactant is the limiting and the calculate the maximum mass of CCl4 that can be formed. Calculate the theoretical yield.

Explanation / Answer

CH4 + 4 Cl2 -----------------------> CCl4 + 4 HCl

16g         284g                                 154g

4g            15g

16 g CH4 needs --------------> 284 g Cl2

4 g CH4 needs --------------> x g Cl2

x = 4 x 284 / 16

x = 71 g

we need actually 71 g Cl2 . but we have only 15 g Cl2 . so it is limiting reagent

Cl2 is limiting reagent

product is based on limiting reagnet

284g g Cl2 will give------------------------> 154g CCl4

15 g Cl2 will give ----------------------> y g CCl4

y = 15 x 154 / 284

y = 8.13 g

maximum mass of CCl4 = theoretical yield = 8.13 g

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