In a certain state, 44% of the residents live in urban areas and the rest live i

Question

In a certain state, 44% of the residents live in urban areas and the rest live in rural areas. A recent poll indicated that 77% of those living in urban areas support candidate alpha, whereas only 33% of those living in rural areas support candidates Alpha.

A: If one citizen from this state is selected at random, what is the probability that he/she is a rural citizen who does not support candidate Alpha?

B: If one citizen from this state is selected at random, what is the probability that he/she lives in an urban area given that he/she supports candidate alpha?

C: If one urban citizen from this state is selected at random, what is the probability that he/she does not support candidate Alpha?

D: If one citizen from this state is selected at random, what is the probability that he/she supports candidate Alpha?

E: If one citizen from this state who does not support candidate Alpha is selected at random, what is the probability that this citizen lives in a rural area?

Explanation / Answer

a)

Probability rural not support candidate alpha = 0.44 - 0.33 = 0.11

b)

Prob = 0.77

c)

Prob = 1 - 0.77 * 1 - 0.33 = 0.23* 0.67= 0.1541

d)

P = 0.77 * 0.33 =0.2541

e

for thsi literal please post it in a new quesiton

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