IM LOOKING FOR AN EXPLANATION OF HOW TO FIND THESE 3 RANKINGS: Rank each wire-ma
ID: 3164012 • Letter: I
Question
IM LOOKING FOR AN EXPLANATION OF HOW TO FIND THESE 3 RANKINGS:
Rank each wire-mass system on the basis of its fundamental wavelength.
Rank each wire-mass system on the basis of its wave speed.
Rank each wire-mass system on the basis of its fundamental frequency.
A combination work of art/musical instrument is illustrated. (Figure 1) Six pieces of identical piano wire (cut to different lengths) are hung from the same support, and masses are hung from the free end of each wire. Each wire is 1, 2, or 3 units long, and each supports 1, 2, or 4 units of mass. The mass of each wire is negligible compared to the total mass hanging from it. When a strong breeze blows, the wires vibrate and create an eerie sound Figure 1 of 1Explanation / Answer
Here, for the fundamental length
as wavelength = 2L
hence , the ranking of wavelength will in the ranking of length
D > A > E = C > B = F
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for the wave speed
wave speed = sqrt(T/u)
T is the tension , u is mass density , as u is same for all wires
the wave speed depend on the tension in wire which depend on the weight suspended
hence , the ranking is
E > A = B > C = D = F
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for the fundamental frequency
f0 = sqrt(T/u)/(2L) = C * sqrt(T)/L (C is a contant)
Now, for the ranking
B > E > F > A > C > D