Please Show ALL WORK!!!!! Part B (2.5 pts) Assuming that there is NO meiotic rec

Question

Please Show ALL WORK!!!!!

Part B (2.5 pts) Assuming that there is NO meiotic recombination between homologous chromosomes during meiosis I during the formation of gametes, what is the number of different gametes possible in humans due to independent assortment of the chromosomes (assume heterozygosity between maternal and paternal homologues)? e.g. how many different chromosome combinations are possible? Now, using this information, how many different zygotic combinations are possible upon fertilization between a human egg and sperm? The answer of this question basically answers what is the possibility of two independent fertilization events producing identical twins. SHOW YOUR WORK AND EXPLAIN YOUR ANSWER

Explanation / Answer

Males = 44 XY

So, males contain 23 pairs of heterozygous chromosomes.

Number of different gametic possibilities = 223

= 8388608

Females also would produce the same number of gametes as it is given that all the chromosomes are heterozygous.

Number of different genotypes possible = 246

= 7.0368744 X 1013

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