Absorbance 420 nm: Protein mix=2.13 Fraction 1=0.746 Fraction 2=0.285 Fraction 3
ID: 317025 • Letter: A
Question
Absorbance 420 nm:
Protein mix=2.13
Fraction 1=0.746
Fraction 2=0.285
Fraction 3= 0.147
Absorbance 280 nm:
Protein mix=0.727
Fraction 1=0.395
Fraction 2=0.385
Fraction 3= 0.341
Abs Abs Tota yield Fold Specific activity 420 600 280 protein (mg) For alkaline phosphatase purification (umol/min/mg) Protein mix Fraction 1 o 7 og 315 Fraction 2 0385 Fraction 3 NT o. Assume the extension coefficient of all these protein at 280 nm is 1 mg/mL/cm. Assume alkaline phosphatase's product has an extension coefficient of 0.1 umol/mL/cm. Which fraction has the most of enzyme?Explanation / Answer
Answer:
From the presented data, it is missing that how much time the test was conducted. Its looking fraction 1 is containing more content and hence probability of maximum presence of enzyme.