Quality Control specialists want to estimate the population average assembly tim

Question

Quality Control specialists want to estimate the population average assembly time from the sample of 16 individual records collected independently. They assume that the individual assembly times are normally distributed with unknown parameters. The sample summaries were found as Sample Mean = 5 minutes and sample variance = 15.21. Describe the 99% confidence interval for the population average assembly time. Critical Values UCL = Upper Confidence Limit = LCL = Lower Confidence Limit = Width of the interval

Explanation / Answer

here for (n-1=15) degree of freedom at 99% CI; critcal values of t =+/-2.9467

std error of the mean =std deviation/(n)1/2 =(15.21/16)1/2 =0.975

UCL =mean +t*std error =2.127

LCL=mean -t*std error =7.873

width =UCL-LCL =5.746

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