The solutions in the two arms of this U-tube are separated by a membrane that is
ID: 317530 • Letter: T
Question
The solutions in the two arms of this U-tube are separated by a membrane that is permeable to water and glucose but not to sucrose. Side A is half-filled with an aqueous solution of 2 mols of sucrose and 1 mol of glucose. Side B is half-tilled with an aqueous solution of 1 mol of sucrose and 2 mols of glucose. Initially, the liquid levels on both sides are equal. A. Initially (before any diffusion takes place), what is the tonicity of side A with respect to (compared to) side B? Isotonic Hypertonic Hypotonic After diffusion and equilibrium: _____ How many mols of sucrose are on side A?_____ side B? _____ How many mols of glucose are on side A?_____ side B? After diffusion what would you observe in the water level in side A? an increase in the water level. no change in the water level a decrease in the water levelExplanation / Answer
1. Firstly we should know that sucrose is disaccharide and glucose is monosaccharide, one sucrose molecule is made up of one glucose and one fructose. Fructose also a monosaccharide.
A side contain 2 moles of sucrose and one mole of glucose, so A side contain total 5 moles of monosaccharide. Likewise side B contain 1 mole of sucrose and 2 moles of glucose, so B side contain total 4 moles of monosaccharide. Side A contain hypertonic solution as compared to side B.
B. 2 mole sucrose on side A and 1 mole on side B
0.5 mole glucose on side A and 2.5 mole glucose on side B
C. Ans: an increase in the water level
We know that in diffusion solvent molecule moves from lower concentration gradient to higher concentration gradient. After diffusion water level of side A will increase.