Refer to the data set in the accompanying table. Assume that the paired sample d
ID: 3181037 • Letter: R
Question
Refer to the data set in the accompanying table. Assume that the paired sample data is a simple random sample and the differences have a distribution that is approximately normal. Use a significance level of 0 05 to test for a difference between the weights of discarded paper (in pounds) and weights of discarded plastic (in pounds). in this example, mu_d is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the weight of discarded paper minus the weight of discarded plastic for a household. What are the null and alternative hypotheses for the hypothesis test? H_0: mu_d notequalto 0 H_1: mu_d = 0 H_0: mu_d = 0 H_1: mu_d 0 H_0: mu_d = 0 H_1: mu_d notequalto 0 identify the test statistic. t = (Round to two decimal places as needed.) identify the P-value. P-value = (Round to three decimal places at needed.) Wheat is the conclusion based on the hypothesis test? Since the P-value is than the significance level, the hypothesis. There sufficient evidence to support the claim that there is a difference between the weights of discarded paper and discarded plastic.Explanation / Answer
The dataset is not given in the question
The hypothesis formulation is
H0 :Ud not equal to zero
H1 : Ud is equal to zero
Now use the data to calculate the t statisitc as
T = (Mean1 - Mean2) /(SD/sqrt(N)) , where the SD is Standard deviation , N is the number of samples or sample size and Mean is the average of the data.
once we calculate the t stat , then we check for the t critical value using the degrees of freedon as N-1
now we calculat the p value using the t table again
now please note that
if P value < 0.05 , then we reject the null hypothesis in favor of alternate hypothesis , else if p value > 0.05 then we fail to reject the null hypothesis and conclude otherwise.
Without the actual data , it is not possible to provide you actual answers