Meme be used onalidence interval for the mean and Enginnering, 2000 83-80) Briti

Question

Meme be used onalidence interval for the mean and Enginnering, 2000 83-80) Britia Columbia. Included were me imponam the cleaning 954 confidence interval for the following statistics de with drianiard wahre Wall be atruct conidence interval from these of total were MD, 90, 100 and 73. 105 B 905 in the rinue. This evercise he ankle "Laheratory Evaluation of Use Suractame ier Ground Remediatin and the Maximun Perntial Regeling Thew D. Lee, R. Cody, and 39,920 0.512 the Camino. be Tile Clawiscation experiments Enginnering uniconazole was 500 of 0002 describes a measure the shade marble lae is which the amount of refleard 20.1A, and amounts absorbed in HE) were te is measured on a scale of 0-55 A Find a 90s confdmoe interval for the mean amount H The following MINITAB presents a aonidelor interval fora population mean One San ple T: X 95E CI StDev 6.51613. 6.67656 0.03546 10 5.59635 0.112 How many offreedom the sudents rdistriletice have a confidence interval. Use the information in the output, along with the ruble to oompute O O O

Explanation / Answer

Confidence Interval:

Here sample size is small (<30 ) and population standard deviation is unknown so we use t-distribution to find the confidence interval.

Data:

x

0.5

2.0

1.4

1.1

We use excel formula to get sample mean and sample standard deviation.

x

0.5

2.0

1.4

1.1

X bar =

=AVERAGE(G3:G6)

s =

=STDEV(G3:G6)

x

0.5

2.0

1.4

1.1

X bar =

1.25

s =

0.6245

Formula:

X bar (-/+) E

X bar = 1.25

E = tc * ( s / sqrt (n)) = tc * ( 0.6245 / sqrt (4))

Here df = n – 1 = 4 - 1 = 3

Level of significance = 100% - 90% = 10%

So at 10% level of significance for 3 degrees of freedom we get the critical value of t as 2.353

E = 2.353 * ( 0.6245 / sqrt (4)) = 0.422

X bar (-/+) E

1.25 (-/+) 0.735

0.52 and 1.98

Answer:

(0.52 to 1.98)

x

0.5

2.0

1.4

1.1

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