I\'m not sure how to go about this question. Any help is welcome! Due a Ive Prob
ID: 3225869 • Letter: I
Question
I'm not sure how to go about this question. Any help is welcome!
Explanation / Answer
It is a question of testing an average (which is estimated as 511 after taking 61 hourly trials). The measurement was taken 61 times and the count could have been e.g. 520, 580, 440, 520...(around the range of 500) and the average of these 61 was 511. We have to test whether this average of 511 being greater than 500 is really possible or did it happen by chance.
The happening by chance is called p-value, after our calculation if our p-value turns to be less than alpha value (which is usually 5%) then we are fairly confident that our average is greater or lesser than the hypothesized value of 500 (greater or lesser is based on our hypothesis)
Let us assume mu1 = 511 (estimated). mu = hypothesied avg = 500
H0: NULL: mu1 = mu
ie. the estimated hourly count is equal to (or less than) the hypothesized hourly count of 500
H1: Alternate: mu1 > mu ie. mu1 > 500
ie. the estimated hourly count is greater than the hypothesized hourly count of 500
The uncertain quantity is the difference of mu1 and mu ie. mu1 - mu. It can take a) negative values in which case the hourly count is lower than the hypothesized 500
b) positive values in which case the the hourly count is greater than the hypothesized 500
c) zero in which case both of them are equal.
Type 1 error - Incorrect rejection of true null hypothesis. When the hypothesized is actually true, but the observed one turns out to be false. We make a type 1 error
Type 2 error - Incorrectly finding out a false null hypothesis. When the hypothesized is actually false, but the observed one turns out to be true. We make a type 2 error.
In our example, when the random hourly count 511 is less than or equal to 500 (meaning the null is true) and we find through our one sample z-test thatn 511 is greater than 500 (proving null is false), then we make a type 1 error
Similarly when the random hourly count 511 is greater than 500 (meaning the null is false) and we find through our one sample z-test that 511 is less than 500 (proving null is true), then we make a type 2 error.
Relative costs of the errors is - when we commit a type1 error, we are buiding a store when in reality it is going to fail. Because the null is true (null is 511 < 500) and we made a false observation 511 > 500 and thought it will be profitable.
When we commit a type2 error, we are not building a store when in reality it is going to be profitable. Because the null is false (null is 511 < 500) and we made an incorrection observation 511 < 500 and thought it will be useless to build a store.
it is the tradeoff between building costs of a store vs missed profit for the period of operations. If building cost is much much higher than the missed profit (which is usually the case), it is best to avoid type1 error. Hence type1 error should be very less, let us say keep it at 0.01
z-statistic = (mu1-mu)/ sqrt(s1^2/n)
= (511 - 500)/sqrt(51^2/61) = 1.6845
p-value = 1- norm.dist(1.6845,true) = 0.046 (since it is a right tailed test as we are testing for >hypothesized mean)
since p-value >0.01, there is more than a random chance of 511 greater than 500
which means fail to reject null hypothesis, meaning - null is true and hence the observed hourly count of 511 is less than the hypothesized hourly count of 500
DONOT build at the designated location