Assume you are drawing two balls without replacement from an urn that contains 1

Question

Assume you are drawing two balls without replacement from an urn that contains 12 green balls, 7 blue balls, and 4 red balls. What is the probability that you will draw a geeen ball and a blue ball? (Hint: there are two ways that this can happen.
The probability that you draw a green and a blue ball is: ???? Assume you are drawing two balls without replacement from an urn that contains 12 green balls, 7 blue balls, and 4 red balls. What is the probability that you will draw a geeen ball and a blue ball? (Hint: there are two ways that this can happen.
The probability that you draw a green and a blue ball is: ????
The probability that you draw a green and a blue ball is: ????

Explanation / Answer

urn contains 12 green balls and 7 blue balls and 4 red balls total = 23

Probablity of drawing green ball first = 12 / 23

Probablity of drawing blue ball first = 7/ 23

probability that you will draw a green ball and a blue ball

First a green ball and the blue ball = 12 / 23 * 7/22

First a blue ball and the green ball = 7/23 * 12/22

probability that you will draw a green ball and a blue ball = 0.33201

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