Assume that x has a normal distribution with the specified mean and standard dev
ID: 3242312 • Letter: A
Question
Assume that x has a normal distribution with the specified mean and standard deviation. Find the indicated probability. (Round your answer to four decimal places.) mu = 4.1: sigma = 2.4 p(3 lessthanorequalto x lessthanorequalto 6) = Assume that x has a normal distribution with the specified mean and standard deviation. Find the indicated probability. (Round your answer to four decimal places.) mu = 14.0: sigma = 4.1 p(10 lessthanorequalto x lessthanorequalto 26) = Assume that x has a normal distribution with the specified mean and standard deviation. Find the indicated probability. (Round your answer to four decimal places.) mu = 25: sigma = 3.4 p(x greaterthanorequalto 30) = Assume that x has a normal distribution with the specified mean and standard deviation. Find the indicated probability. (Round your answer to four decimal places.) mu = 2.7: sigma = 0.31 p(x greaterthanorequalto 2) =Explanation / Answer
Answer:
1).
Z value for 3, z=(3-4.1)/2.4 = -0.46
Z value for 6, z =(6-4.1)/2.4 = 0.79
P( 3x6)= P( -0.46<z<0.79)
=P( z<0.79)-P( z <-0.46)
=0.7852-0.3228
=0.4624
2).
Z value for 10, z =(10-14.0)/4.1 = -0.98
Z value for 26, z =(26-14.0)/4.1 = 2.93
P( 10x26)= P( -0.98<z<2.93)
=P( z<2.93)-P( z <-0.98)
=0.9983-0.1635
=0.8348
3).
Z value for 30, z=(30-25)/3.4 =1.47
P(x 30) = P( z >1.47)
=0.0708
4).
Z value for 2, z=(2-2.7)/0.31 =-2.26
P(x 2) = P( z >-2.26)
=0.9881