Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Assume that x = 1.32 m and y = 1.98 m. What is the speed of the water coming out

ID: 1442296 • Letter: A

Question

Assume that x = 1.32 m and y = 1.98 m. What is the speed of the water coming out of the hole?

If the hole has a diameter of 3.17 mm, then what is the height, h, of the water level in the tank?

- Chrome File Edit View History Bookmarks People Window Help 0 0 0 D chem252, 2nd review hand x VR Sig in to your account x Yg LON-CAPAW Water jet In 1656, The Burgmeister ( x | 0 0 t 55% D 3 ) Tue 3:04 PM Q = You G C 8 https://s1lite.msu.edu/res/msu/textbook/serway/Chap09/prob0945mal. problem?symb=uploaded%2fmsu%2f63152883c582567dmsul1%2fdefaul _12883.. * Aso a Main Menu Contents | Grades | PM 1 d Course Contents » .. > Homework Set #7 (due 3/22 at 11:59PM) » Water jet 4G O Timer O Notes a Evaluate or a feedback D Print 9 Info A jet of water squirts out horizontally from a hole near the bottom of the tank, as seen in the figure. Assume that X = 1.32 m and y = 1.98 m. What is the speed of the water coming out of the hole? Submit Answer Tries 0/20 If the hole has a diameter of 3.17 mm, then what is the height, h, of the water level in the tank? Submit Answer Tries 0/20 e Post Discussion Send Feedback 2 O 2 O 1 N O % GA, . g o WA HU

Explanation / Answer

Since y = 1.98m,

t^2 = 2 y / g

t = sqrt(2 y / g)

t = sqrt(2* 1.98 /9.81 ) 0.635 secs

Velocity V = S/t

V = 1.32/0.635

V = 2.34 m/s
-------------------------------


By Torricelli's law, v = sqrt (2gh)


v^2 = 2 g h

h = 0.5 v^2 / g

h = 0.5 * (2.34^2) / 9.81

h = 0.28 m this is above the hole

Thus water level is h + y

= 0.28 + 1.98

= 2.26 m