Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

The following ANOVA table, based on information obtained for three samples selec

ID: 3243396 • Letter: T

Question

The following ANOVA table, based on information obtained for three samples selected from three independent populations that are normally distributed with equal variances, has a few missing values.

Source of

Variation

Degrees of

Freedom

Sum of

Squares

Mean

Square

Value of the

Test Statistic

Between

2

II

19.2813

Within

89.3677

III

F = ___V__ = VII

VI

Total

12

IV

a) Find the missing values and complete the ANOVA table. Round to four decimal places.

b) Using = .01, what is your conclusion for the test with the null hypothesis that the means of the three populations are all equal against the alternative hypothesis that the means of the three populations are not all equal?

i. Reject H0. Conclude that the means of the three populations are equal.

ii. Reject H0. Conclude that the means of the three populations are not equal.

iii. Do not reject H0. Conclude that the means of the three populations are equal.

iv. Do not reject H0. Conclude that the means are of the three populations are not equal.

Source of

Variation

Degrees of

Freedom

Sum of

Squares

Mean

Square

Value of the

Test Statistic

Between

2

II

19.2813

Within

89.3677

III

F = ___V__ = VII

VI

Total

12

IV

Explanation / Answer

(a)

(I) within df=total df-between df=12-2=10 ( df=degree of freedom)

(II)sum of square(SS)=Mean Square(MS)*df

so Between SS=19.2813*2=38.5626

(III)Mean Square(MS)=Sum of Square/df

Within MS=89.3677/10=8.9368

(IV) Total SS=between SS+Within SS=38.5626+89.3677=127.9303

(V)F=BEtween MS/Within MS=19.2813/8.9367=2.16

(VI) critical F(0.01,2,10)=7.56

(b) since critical F=7.56 is more than calcuated F=2.16 , so we fail to reject H0 and conclude that

Conclude that the means of the three populations are equal.

right choice is iii. Do not reject H0. Conclude that the means of the three populations are equal.

Source of Degrees of Sum of Mean Value of the Variation Freedom Squares Square Test Statistic Between 2 38.5626 19.2813 Within 10 89.3677 8.93677 2.157524475 Total 12 127.9303 7.5594