Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Math- statistics - need help with problem 1-31(a-f) - please fully explain the a

ID: 3270192 • Letter: M

Question



Math- statistics
- need help with problem 1-31(a-f)
- please fully explain the answer to following questions
- information is all there in the picture
- thank you

With your team, brainstorm ways that you could compare the two groups of i Recall some of the measures of central tendency from Lesson 1.l.1. rogs. 2008 2009 Frog Name Jump Length Frog Name Jump Length Skeeter Eater Warped Greg Crome Dome R.G The Well Ain't Dry Winner 7 lb 8 oz. Baby Delbert Sr. 231.5 in. For the Sign 252 in. 236.5 in. 231.5 in. 226.75 in. 221.5 in. Spare the Air Everyday 223.25 in. 223.25 in. 222.25 in. 185.25 in. 230 in. Alex Frog 229 in. Shakit 227 in. Six Mile Shooter 220.5 in. Hooper 217 in. Jenifer's Jumper 216.5 in. |Dr. Frog

Explanation / Answer

(a)

Since the data for 2008 does not have an outlier and also the sample size is small, so the median would be a better estimate of the data's central tendency ( the 'typical' jump ).

(c)

The median should not change by much, but the mean should decrease significantly.

(d)

Before the addition of outlier:

Mean = 224.125

Median = 224.25

After the addition of outlier:

Mean = 217

Median = 221.5

(e)

In this case the mean will be a better choice to predict the typical jump, because now the data has an outlier.

(f)

Median is better than mean, when sample sizes are small and the data does not have any outliers.

Hope this helps !