College Physics I (1401 Grace Perlod: 8 days left | Register No Cutnell, Physics

Question

College Physics I (1401 Grace Perlod: 8 days left | Register No Cutnell, Physics, 10e Gradebook ORION Downloadable eTextbook BACK Chapter 02, Problem 09 A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 5.23 mys. The car is a dstance d away. The bear is 244 m behind the tourist and running at 7.15 m/s. The tourist reaches the car safely. What is the maximum possible value for d the tolerance is +/-2% Click if you would Wke te Show Work for this question Qoen Show Work MacBook Air 8 5 option

Explanation / Answer

Given,

Speed of man = 5.23 m/s

Speed of bear = 7.15 m/s

Distance = 24.4 m

So, every second the bear gains (7.15 - 5.23) = 1.92 m/s

The bear has 24.4 meters to travel

24.4/1.92 = 12.71 s, it takes bear to catch

So, distance, d = v x t = 5.23 x 12.71 = 66.47 m

Please rate my answer if you find it helpful, good luck...

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