College Physics Exam #2 ) Name:Toda MOCK 0 Student ID#: Score: Problem 1: The el

Question

College Physics Exam #2 ) Name:Toda MOCK 0 Student ID#: Score: Problem 1: The electron beam The magnetic field causes the beam to follow a circular path as enters a region of uniform magnetic field perpendicular to the beam. in the diagram below ·F-8.1x10"W unform B fieid acts into plane of screen I paper The speed acquired by each electron is 2.5 107 m/s and the force experienced by the electron is about 8.8 x 10-15 N. (Mass of electron is 9-1x10 Ko and for proton is 1 67 10 Kg) a) What should be the radius of this circular path?xib ms) b) I f we change the electron beam to proton beam with same speed and force, what should be the radius for proton?15alm c) Compare radius for proton and electron. The cous fae srcitn has ueof on elechan beom and fur eletton has less the mbthon brome D difkaert for the prolin ond election

Explanation / Answer

1. given speed of each electron v = 2.5*10^7 m/s

force F = 8.8*10^-15 N

m = 9.1*10^-31 kg

mp = 1.67*10^-27 kg

a. let the radius of the circular path be r

then

mv^2/r = F

r = 6.463 cm

b. for proton, mp*v^2/r = F

r = 113.636 m

c. the raius of proton is far more than radius of electron as mass of proton is far more than mass of electron

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---