Please explain! Thank you (B) Show that the capacitance of the original capacito
ID: 3308481 • Letter: P
Question
Please explain!
Thank you
(B) Show that the capacitance of the original capacitor is unaffected by the insertion of the metallic slab if the slab is infinitesimally thin. In the result for part (A), let a 0: c = lim Finalize The result of part (B) is the original capacitance before the slab is inserted, which tells us that we can insert an infinitesimally thin metallic sheet between the plates of a capacitor without affecting the capacitance. We use this fact in the next example MASTER IT HINTS: GETTING STARTED I I'M STUCKI Consider a parallel-plate capacitor having area A = 0.50 m2 and separation d = 0.016 m (a) The capacitor is first attached to a battery having voltage 9 V. What are Q (in pC) and (b) Now, the battery is removed, and a metallic slab of thickness a are Q (in pC) and 0.006 m is inserted. what (c) Finally, the battery is reattached. what are (in pC) and pCExplanation / Answer
Given,
a = 0.5 m^2 ; d = 0.016 m ; V = 9 V
a)We know that,
C = e0 A/d
C = 8.85 x 10^-12 x 0.5/0.016 = 276.6 x 10^-12 C
Q = CV = 276.6 x 10^-12 x 9 = 2489 x 10^-12 C
Hence, Q = 2489 x 10^-12 C ; delta-V = 9 V
b)Using conservation of charge, it remains same as above.
But the new capacitance is:
C = 8.85 x 10^-12 x 0.5/0.006 = 737.5 x 10^-12 C
V = Q/C = 2489 x 10^-12/737.5 x 10^-12 = 3.38 V
Hence, Q = 2489 pC ; delta-V = 3.38 V
c)Delta-V = 9 V
Q = 737.5 x 9 = 6637.5 pC
Hence, Q = 6637.5 pC ; delta-V = 9