A sample of 10 waiting times at a bank using the new single waiting line configu

Question

A sample of 10 waiting times at a bank using the new single waiting line configuration has a standard deviation of 0.5 minute. Assume the population of wait times for the single waiting line configurat is normally distributed. You configuration have a standard deviation that is less than 1.8 minutes. 12. want to use a significance level of 0.05 to test the claim that the wait times for the new waiting line a) State the null and alternative hypotheses, and identify which one is the claim 5 pts) Hi: (4 pts) b) Calculate the test statistic. Round to 3 decimal places

Explanation / Answer

Given that,
population standard deviation ()=1.8
sample standard deviation (s) =0.5
sample size (n) = 10
we calculate,
population variance (^2) =3.24
sample variance (s^2)=0.25
null, Ho: =1.8
alternate, H1 : <1.8
level of significance, = 0.05
from standard normal table,left tailed ^2 /2 =16.919
since our test is left-tailed
reject Ho, if ^2 o < -16.919
we use test statistic chisquare ^2 =(n-1)*s^2/o^2
^2 cal=(10 - 1 ) * 0.25 / 3.24 = 9*0.25/3.24 = 0.69
| ^2 cal | =0.69
critical value
the value of |^2 | at los 0.05 with d.f (n-1)=9 is 16.919
we got | ^2| =0.69 & | ^2 | =16.919
make decision
hence value of | ^2 cal | < | ^2 | and here we do not reject Ho
^2 p_value =0.9999
ANSWERS
---------------
null, Ho: =1.8
alternate, H1 : <1.8
test statistic: 0.69
critical value: -16.919
decision: do not reject Ho

we have no evidence to support the claim

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---