Consider a system consisting of four components, as pictured in the following di
ID: 3328034 • Letter: C
Question
Consider a system consisting of four components, as pictured in the following diagram Components 1 and 2 form a series subsystem, as do Components 3 and 4. The two subsystems are connected in parallel. Suppose that P(1 works)-.7 2 works) = .7 R3 works) = .7 P 4 works).7 and that the four components work independently of one another. (a) The 1-2 subsystem works only if both components work. What is the probability of this happening? 0.49 (b) What is the probability that the 1-2 subsystem doesn't work? 0.51 What is the probability that the 3-4 subsystem doesn't work? 0.51 (c) The system won't work if the 1-2 subsystem doesn't work and if the 3-4 subsystem also doesn't work. What is the probability that the system won't work? 0.2601 What is the probabiltythat it will work? 0.7399 (d) How would the probability of the system working change if a 5-6 subsystem were added in parallel with the other two subsystems? (Give the answer to four decimal places.) 0.1176 It increases (e) How would the probability that the system works change if there were three components in series in each of the two subsystems? (Give the answer to four decimal places.)Explanation / Answer
a) P(1-2 subsystem working) = 0.7x0.7 = 0.49
b) P(1-2 sub system not working) = 1 - 0.79 = 0.51
c) P(system wont work) = 0.51 x 0.51 = 0.2601
P(it will work) = 1 - 0.2601 = 0.7399
d) If 5,6 subsystem is added in parallel, P(working) = 1 - P(3 subsystems failing together)
= 1 - 0.51 x 0.51 x 0.51
= 1 - 0.1327
= 0.8673
It increases
e) If 3 components are added in series, P(system works a subsytem working) = 0.7x0.7x0.7 = 0.343
P(a subsystem not working) = 1 - 0.343 = 0.657
So, P(system works) = 1 - 0.657x0.657 = 0.5684