Men and women in happy manages tend to harvee lowr blood pressure then single pe
ID: 3331482 • Letter: M
Question
Men and women in happy manages tend to harvee lowr blood pressure then single people A mychologht s hntd h stuthying wonen wth h ood pressure SyilHood pressure scores for momen tollow Note: To fird the probablity above or bdowzcore, click on the normal curve koon with one Ine, and posltion the lne t the approprite 2-score on the hortzontal axds The areas under the standard normal curve shove and below the z-scare ll be -apedthe let rd right of the vetkal Ire, espethdy. To find the probablity betweentro zaares, d kon te na mal arve knwkh two lies, ard Podhr the left Ine otthe louer z-score tr d the right Ire the tigher z-score. The en a under the normal curve behween the vertical lines wll be displayed in blue ThE highest Posbiez-sare that is st1 h the botom 99% ofthe sytihloodp sure drrbutonk:- Use thb z-score to dstormine X, the coresponding sydtlic blood pressure scnne This sa re, X, t; th. Part tie of syste blood sure sms "nengwomen. The pertene rank of this sare's " deed stage 1-petension what pertetag, "omen hne stere Sy tak biood pressure between 140 biood pressure in this raniger d i o 11.13% o 9.01% O 13.13% 020.13 0 25.425 21.19%Explanation / Answer
We have been given the params of normal curve : Mean = 110, sigma = 25
We use these params to standardize the distribution :
1. Highest Z for bottom 95% is at 1.645
2.The corresponding X is Mean+Z*Sigma = 110+1.645*25 = 151.125
3. The score X is the 95 percentile of sys blood pressure states among women. The percentile rank of this score is 95%
4. P(140<X<150) = P(140-110/25<Z<159-110/25) = P(1.2<Z<1.6) = .975-.8849 = .0901 = 9.01% option C
5. P(X<90) = P(Z< (90-110)/25) = P(Z<-.8) = .2119 or (option C 21.19%)