Submit Answer Save Progress 6. O-1 points MStatCC9 19.E.024. 0 Your our company
ID: 3334587 • Letter: S
Question
Submit Answer Save Progress 6. O-1 points MStatCC9 19.E.024. 0 Your our company operates a van service from the airport to downtown hotels. Each van carries seven passengers. Many passengers who reserve seats don't show up-in fact, the probability is 0.2 that a randomly chosen passenger will fail to appear. Passengers behaviors are independent. If you allow nine reservations for each van, what is the probablity that more than seven passengers will appear? Do a simulation to estimate this probabillty, (Using line 102 of this table of random digits, simulate 10 vanloads. Let 0-1 be a pass@nger failing to appear and 2-9 be a passenger appearing.) eBook Submit Assignment Save Assignment Progress Home My Assignments Extension Reques 314248037165103 62253 50490 61181 69183 final example has stages that are not independent. That is, the probabilities at one 70639 93417 41448 7559Explanation / Answer
We will take line 102.
Vanload 1: We will check first 9 numbers and see that
0-1 : 1 ; 2-9 : 8
Vanload 2 : Next 9 random numbers and
0-1 : 5; 2-9 : 4
Vanload 3 : Next 9 random numbers and
0-1 : 0; 2-9 : 9
Vanload 4 : Next 9 random numbers and
0-1 : 0; 2-9 : 9
Vanload 5 : Next 9 random numbers and
0-1 : 2; 2-9 : 7
Vanload 6 : Next 9 random numbers and
0-1 : 3; 2-9 : 6
Vanload 7 : Next 9 random numbers and
0-1 : 0; 2-9 : 9
Vanload 7 : Next 9 random numbers and
0-1 : 0; 2-9 : 9
Vanload 8 : Next 9 random numbers and
0-1 : 0; 2-9 : 9
Vanload 9 : Next 9 random numbers and
0-1 : 2; 2-9 :7
Vanload 10 : Next 9 random numbers and
0-1 : 2; 2-9 :7
We can see that there are 6 times more than 7, members are appearing.
So Pr(more than 7 people are appearing) = 6/10 = 0.6