Submit Answer Save Progress Practice Another Version 114 points 1 Previous Answe
ID: 1886128 • Letter: S
Question
Submit Answer Save Progress Practice Another Version 114 points 1 Previous Answers OSUniPhys1 3.4P061. My Notes Ask Your Te A woodpecker's brain is specially protected from large decelerations by tendon-like attachments inside the skul. While pecking on a tree, the woodpecker's head comes to a stop from an initial velocity of 0.550 m/s in a distance of only 1.90 mm. (a) Find the acceleration in m/s and in multiples of g (g 9.80 m/s?). (Enter the magnitudes.) in m/s? in multiples of g m/s2 .7961 8.12 X (b) Calculate the stopping time (in s). 6.9E-3 ling the brain stretch, making its stopping distance 4.25 mm (greater than the head and, hence, less deceleration of the brain). What is the brain's deceleration, expressed in multiples of g? (Enter the magnitude.) Additional Materials eBook 32913 2245504. Jp s 40948946.2580347.jpg40943305,2342067 ipg Show All X 5 6 7 8 9 0Explanation / Answer
(A) vi = 0.550 m/s
vf = 0 and d = 1.90 x 10^-3 m
vf^2 - vi^2 = 2 a d
0^2 - (0.550^2) = 2(1.90 x 10^-3 ) a
a = - 79.6 m/s^2
magnitude = 79.6 m/s^2
a = (79.6 / 9.8) g = 8.12
Ans: 79.6 m/s^2
8.12
(B) vf = vi + a t
0 = 0.550 - 79.6 t
t = 6.9 x 10^-3 s
(C) vf^2 - vi^2 = 2 a d
0^2 - 0.550^2 = 2(a)(4.25 x 10^-3)
a = - 35.6 m/s^2
magnitude in g = (35.6/9.8) = 3.63