Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Please help. show work!! 1) For the function F(x) = x + sin (2x) on [0, pi] Find

ID: 3341356 • Letter: P

Question

Please help. show work!!


1) For the function F(x) = x + sin (2x) on [0, pi] Find all intervals of increase and decrease.


2) For the function F(x) = sin^2x - 2 cos x on [0, pi] Find all intervals of increase and decrease


3) For the function F(x) = x^4 - 2x^2 + 3 on [-2,3] Find all intervals of increase and decrease


4) For the function F(x) = x / x^2 + 1 on [0,2] Find all intervals of increase and decrease


5) For the function F(x) = x^3 - 27x - 20 on [-3,5] Find all intervals of increase and decrease

Explanation / Answer

1) f'(x) = 1 + 2cos(2x)


For increase,

f'(x) >= 0 => (1+2cos(2x) ) >= 0 => cos(2x) >= -1/2 => x = [0,pi/3] U [2pi/3,pi]


For decrease,

f ' (x) <= 0 => x = [pi/3, 2pi/3]


2) f ' = 2sinxcosx + 2sinx = 2sinx(cosx+1)


For increase, f ' >= 0

=> 2sinx(cosx + 1) >= 0 => x = [0, pi]


For decrease, f ' <= 0

f does not decrease in [0, pi]


3) f ' = 4x^3 - 4x = 4x(x-1)(x+1)


For increase, f ' >= 0

=> 4x(x-1)(x+1) >= 0 => x = [-1, 0] U [1, 3]


For decrease, f ' <= 0

=> x = [-2, -1] U [0, 1]


4) f ' = ( 1 - x^2 ) / (x^2 + 1)^2 = (1-x)(1+x) / (x^2 + 1)^2


For increase, f ' >= 0

=> (1-x)(1+x) / (x^2 + 1)^2 >= 0 => x = [0, 1]


For decrease, f ' <= 0

=> x = [1, 2]


5) f ' = 3x^2 - 27 = 3(x-3)(x+3)


For increase f ' >= 0

=> 3(x-3)(x+3) >= 0 => x = [3, 5]


For decrease, f ' <= 0

=> x = [-3, 3]