Please help. I believe I am over thinking this and missing the easy. Find the sl

ID: 3342591 • Letter: P

Question

Please help. I believe I am over thinking this and missing the easy.

Find the slope of the curve y=x^2-2x-3 at the point (2,-3). Find the equation of the tangent line to the curve at P (2,-3)

Also, this problem.

y=x^3-9x at (2,-10) Find the slope of the curve and the equation of the tangent line.

I keep working these problems and am not coming up with the answer the computer is giving me.

Please show all steps so I can figure out where I am going wrong and won't keep making the same mistake! thanks!

slope = dy/dx

SO, slope = 2x - 2

At (2,-3)

Slope = 2*2 - 2 = 2

tangent : y - y1 = dy/dx (x-x1)

So, y+3 = 2(x - 2)

So, 2x - y - 7 = 0

slope = dy / dx = 3*x^2 - 9

So, at 2, -10

slope = 3 * 4 - 10 = 2

so, tangent : y + 10 = 2 (x - 2)

So, 2x - y - 14 = 0