Consider a system, of a rail-like input connector transferring input current goi
ID: 3349532 • Letter: C
Question
Consider a system, of a rail-like input connector transferring input current going (downward) and delivering power to a slider, the slider also delivers current-while moving to other components, the current is always in the downward(-y) direction.
The following diagrams (1-3) are composed of different frames of time, one at the initial stage where there is no motion(diagram1), another in the stage of change in position (digram2 - midway), and finally the last frame that has no motion and the slider has reached the final input connector(diagram3).
NOTE: The slider, is moving from an exterior force.
From the start, till the end:
1) Is there a Lorentz force in the 3-frames? Explain.
2) In what direction is the Lorentz force, and why?
3) Is there an induced EMF? On what components (slider, or input connector(gray)) and what direction?
Please explain.
Diagram 1:
Diagram 2:
Diagram 3:
intial positionExplanation / Answer
We know that
Lorentz Force=qE+q(vxB)
q is charge , v is velocity , B is magnetic field .
1)
Since there is no velocity in frame 3
Hence , Lorentz force becomes 0
Hence , no Lorentz force
2)
The direction of magnetic field is given by . As we know that magnetic field direction is given by curling the fingers arround the current carrying conductor .
Now , using Lorentz force rule .
Direction of vxB gives direction of Lorentz force
Direcion of force is given as along that of direction of conductor using vector cross multiplication rule .
3)
emf = (Change in flux)/(Change in time)
=B.A/t
=BvL
L is length of conductor
v is velocity
B is magnetic field