Submit Test Test: POST UNIT 7-TEST- Ch. 10 This Question: 1 pt 12 of 13 (5 compl
ID: 3368177 • Letter: S
Question
Submit Test Test: POST UNIT 7-TEST- Ch. 10 This Question: 1 pt 12 of 13 (5 complete) This Test: 13 pts possibl EQuestion Help lang ten sta d that the mean len ahire of lunan is 9eeF However two tesearchers onervey noh/edith e sub ed hought hatheme an temperature of humans i, is tan 98-F approach to undad a hypohesis test tojudge whether the mean terpeatue of hurmans is. less t an986"F·the a-001leved of signikance tale the hypotheses 1hey measa red the temperatures of 5a healthy adults 1 to 4 Simes daily for 3 days, oltaining 225 meaurements The sample data resulted in a sample mean of 98 3 F and a sample standard devilation o1F. Use the Pvalue 96 Find the test statotc Rond to two decind places as needed) The Pval Round to ree decimal places as needed Whal can be concled C Reject Hy since the P value is t ss than he significance leveExplanation / Answer
Solution:-
State the hypotheses. The first step is to state the null hypothesis and an alternative hypothesis.
Null hypothesis: u > 98.6
Alternative hypothesis: u < 98.6
Note that these hypotheses constitute a one-tailed test.
Formulate an analysis plan. For this analysis, the significance level is 0.01.
Analyze sample data. Using sample data, we compute the standard error (SE), degrees of freedom (DF), and the t statistic test statistic (t).
SE = s / sqrt(n)
S.E = 0.07333
DF = n - 1
D.F = 224
t = (x - u) / SE
t = - 4.091
where s is the standard deviation of the sample, x is the sample mean, u is the hypothesized population mean, and n is the sample size.
The observed sample mean produced a t statistic test statistic of - 4.09
Thus the P-value in this analysis is less than 0.0001.
Interpret results. Since the P-value (almost 0) is less than the significance level (0.01), we have to reject the null hypothesis.
(D), Reject H0, since the p-value is less than the significance level.