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Problem 1: A tetrahedrul die is a four-sided die with equally symmecric faces wi

ID: 3368429 • Letter: P

Question

Problem 1: A tetrahedrul die is a four-sided die with equally symmecric faces with numbers from 1 to 4 fair The other one is biased. The iased one lands on 4 with probability equal to and on the othet three mumbers ench with probability written on it. A person has s pair of tetrahedral die. One of them is A random experiment is performed where a pair such dioe are fipped i) Write down a sample space with the (ii) Use the probability measure to determine the probali ity of rolling six as ocrect probability measure to model this experiment. sum.

Explanation / Answer

Solution

Let X = number on the top face of the fair die and Y = number on the top face of the biased die. Then, P(X = 1) = P(X = 2) = P(X = 3) = P(X = 4) = ¼ …………………….(1) and

P(Y = 1) = P(Y = 2) = P(Y = 3) = 2/9, P(Y = 4) = 1/3 …………………….(2)

Back-up Theory

Since the number on the top face of the fair die does not depend on what number comes on the top face of the biased die, X and Y are independent ……………………..(4) and hence

P(X = x, Y = y) = P(X = x) x P(Y = y)…………………………………………..(5)

Part (I)

Vide (1), (2) and (5), the sample space alongwith the joint probability distribution of X and Y are given below:

x,p(x)

y,p(y)

Total

1, 2/9

2, 2/9

3, 2/9

4, 1/3

1, ¼

2/36

2/36

2/36

1/12

9/36 = ¼

2, ¼

2/36

2/36

2/36

1/12

9/36 = ¼

3, ¼

2/36

2/36

2/36

1/12

9/36 = ¼

4, ¼

2/36

2/36

2/36

1/12

9/36 = ¼

Total

8/36 = 2/9

8/36 = 2/9

8/36 = 2/9

8/36 = 2/9

1

  DONE

Part (II)

Let S = sum of the numbers on the top face of the two dice. Then, S = X + Y.

Various possibilities, (x, y) of getting S = 6 and the respective probabilities are given below:

P(2, 4) = 1/12, P(3, 3) = 2/36, P(4, 2) = 2/36. Thus, P(S = 6) = (1/12) + (2/36) + (2/36)

= 7/36 ANSWER

x,p(x)

y,p(y)

Total

1, 2/9

2, 2/9

3, 2/9

4, 1/3

1, ¼

2/36

2/36

2/36

1/12

9/36 = ¼

2, ¼

2/36

2/36

2/36

1/12

9/36 = ¼

3, ¼

2/36

2/36

2/36

1/12

9/36 = ¼

4, ¼

2/36

2/36

2/36

1/12

9/36 = ¼

Total

8/36 = 2/9

8/36 = 2/9

8/36 = 2/9

8/36 = 2/9

1